If 4.50 g of methane gas (CH4) is introduced into an evacuated 2.00 L container at 35 degress C, what would be the pressure in atmosphere ?
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Expert's answer
2013-05-17T10:13:13-0400
To calculate the pressure we can use the formula:
PV = nRT
where P - the pressure n - amount of substance V - the volume T - the temperature R - universal gas constant P = nRT / V = (4.50 g CH4 / 16.04257 g CH4/mol) x (0.08205746 L atm/K mol) x (35 + 273 K) / (2.00 L) = 3.54 atm
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