Answer to Question #295449 in Physical Chemistry for feyintola

Question #295449

a solution of gold (3) trioxonitrate (5) is electrolysed using a current of 25mA until 1.2g of gold is deposited at the cathode . what is the amount of electricity that would have passsed through the solution. and how long will it take for such an amount of gold to be deposited. then calculate the volume of the gas liberated at the anode.


1
Expert's answer
2022-02-10T07:03:02-0500

Faradays constant =96485=96485

Molar mass of Gold =196.967g/mol=196.967g/mol


Au3++3e^{3+}+3e^-\to Au(s)_{(s)}

1 mole of Au3+^{3+} requires 3 faradays


Charge required for 1.2g

1.2196.967×3×96485\frac{1.2}{196.967}×3×96485


=1763.5C=1763.5C

251000t=1763.5\frac{25}{1000}t=1763.5


t=70540t=70540 seconds




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