Answer to Question #293779 in Physical Chemistry for Roman

Question

3 Cu  +   8HNO₃   g 3 Cu(NO₃)₂   +  2 NO  +  4  H₂O

In the above equation, how many moles of NO can be made when 74 moles of HNO₃ are consumed?

Answer 1

HNO$_3:$ NO $=8:2$

74 moles of HNO$_3$ yields

$\frac{74}{8}×2$ moles of NO

$=18.5$ moles of NO