Question

7.23 × 1024 Al atoms =  [   ] grams Al

Answer 1

Molar mass of Al $=26.982g$

Avogadro's constant $=6.022×10^{23}$

Number of gram of Al$=\frac{7 .23×10^{24}}{6.022×10^{23}}×26.982$

$=323.945g$