Question

A galvanic cellis applied by the combination of fe rodimmersed in feso4 solution of concentration 0.25M

Answer 1

$Fe^{2+}_{(aq)}+2e^-\to\>Fe_{(s)}$ $E^{\theta}=-0.44$

If the cell has Fe rod in FeSO$_4$ at concentration of 0.25M and Cu rod in copper solution of 0.45M

Then E.M.F can be calculated as follows;

$E^{\theta}_{cell}=E^0_{Cu^{2+}/Cu}-E^0_{Fe^{2+}/Fe}=0.34-(-0.44)$

$=0.78$

$E^{\theta}_{cell}=0.78+\frac{0. 0592}{2}\>log\>\frac{0.25}{0.45}$

$=0.77V$