A galvanic cellis applied by the combination of fe rodimmersed in feso4 solution of concentration 0.25M
"Fe^{2+}_{(aq)}+2e^-\\to\\>Fe_{(s)}" "E^{\\theta}=-0.44"
If the cell has Fe rod in FeSO"_4" at concentration of 0.25M and Cu rod in copper solution of 0.45M
Then E.M.F can be calculated as follows;
"E^{\\theta}_{cell}=E^0_{Cu^{2+}\/Cu}-E^0_{Fe^{2+}\/Fe}=0.34-(-0.44)"
"=0.78"
"E^{\\theta}_{cell}=0.78+\\frac{0.\n0592}{2}\\>log\\>\\frac{0.25}{0.45}"
"=0.77V"
Comments
Leave a comment