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Answer to Question #287136 in Physical Chemistry for Bill
Question #287136
How many grams of HF can be prepared if 75.0 g of H2SO4 and 63.0 g of CaF2 are used? (Hint: must find which is the limiting reagent
Expert's answer
mol H2SO4=75g × 1mol/98.08g =0.765
mol CaF2 = 63g × 1mol/78.07g =0.807
g HF=0.765mol H2SO4 × 2mol HF/1mol H2SO4 × 20.01g/mol HF
= 30.6g of HF
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