Question

100g of an unknown metal at 150°C was dropped into a bucket containing 50g of water initially at 21°C.The final temperature of the mixture was 32°C.What is the specific heat capacity of the unknown metal?

Answer 1

Taking specific heat capacity of water as $4200J/(Kg.K)$

Let c$=$ specific heat capacity of the metal

Heat lost by metal$:$

$=\frac{100}{1000}×c×(150-32)$

$=11.8cJ$

Heat gained by water

$=\frac{50}{1000}×4200×(32-21)$

$=2310J$

$11.8c=2310$

$c=195.76J/(Kg.K)$