Unknown concentration of 100.0 mL diprotic acid is titrated against 1.0 M NaOH. The initial burette reading was 1.3 ml, and the final burette reading during the end point was 19.6 ml. What is the concentration of the acid?
Let Concentration of Diprotic Acid is Y M .
100 ml of Y M Diprotic Acid have
Milli Moles of Diprotic Acid = 100 × Y .
Milli geq of Diprotic Acid = 100 × Y × 2
= 200 Y .
Volume used for NaOH = ( 19.6 - 1.3 ) ml .
Molarity of NaOH = 1 M .
Millimoles of NaOH = ( 18.3 × 1 ) .millimoles
Milli geq = 18.3
Milligeq of Acid and Milligeq of base should be equal .
200 Y = 18.3
Y = 18.3 / 200 = 0.0915 M .
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