Task:
calculate the mass of 400 mL of CO2 collected over water at 30 degrees celsius and 749 mm Hg, The vapor pressure of water at 30 degrees Celsius is 31.8 mm Hg
Solution:
The Ideal gas Law allows to calculate the amount of CO₂.
The Ideal Gas Law:
P - pressure (atm)
V - volume (L)
n - the number of moles
R - the universal gas constant (0.082 atm · L / (mol · K))
T - Kelvin temperature
We have to convert mm Hg to atm
1 atm = 760 mm Hg
The conversion factor is
P (atm) = 749 · 1/760 = 0.986 atm
We also have to convert temperature in degrees Celsius to Kelvins
T(K) = 30 + 273 = 303 K
The number of moles of CO₂ is
n(CO₂) = P · V / (R · T) = 0.986 · 0.400 / (0.082 · 303) = 0.016 mol
The mass of CO₂ is
m(g) = n(mol) · MW(CO₂)
MW(CO₂) = MW(C) + 2 · MW(O) = 12 + 2 · 16 = 44 g/mol
m(CO₂) = 0.016 · 44 = 0.704 g
Answer: m (CO₂)) = 0.704 g