Answer to Question #283639 in Physical Chemistry for Ruru

Question #283639

30g of NaOH was dissolved in 80ml of water.The temperature increased from 27°C to 70°C.Estimate the enthalpy change for the dissolution of NaOH

1
Expert's answer
2021-12-31T03:31:01-0500

ΔH=mcΔT\Delta H= mc\Delta T

Assuming density of solution=1g/ml= 1g/ml

and taking c=4.2kJ/(kg.K)c=4.2kJ/(kg.K)


ΔH=801000×4.2×(7027)\Delta H = \frac{80}{1000}×4.2×(70-27)


=14.448kJ=14.448kJ


Molar enthalpy of dissolution:


=4030×14.448=19.264kJ=\frac{40}{30}×14.448=19.264kJ


ΔHdiss=19.264kJmol1\therefore \Delta H_{diss}=-19.264kJ\>mol^{-1}




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