Question

Calculate the volume of NH3 gas at STP when 84 g of N2 is reacted with H2

Answer 1

$N2 ​+3H2 ​⟶2NH3$

Moles of N2$=\frac{84}{28}=3moles$

Mole ratio = 1:3

Moles of H3$=3×3=9moles$

Moles of NH3 $=2×3=6 moles$

Volume $=6×22.4=134.4litres$