Calculate the mass of the solute in 0.1 L of a 5.04x103 M cholesterol solution (C27H460
Question
Calculate the mass of the solute in 0.1L0.1L0.1L of a 5.04×10−3M5.04×10^{-3}M5.04×10−3M cholesterol solution C27H46OC_{27}H_{46}OC27H46O
SOLUTION
Molar mass of C27H46OC_{27}H_{46}OC27H46O
=386.65g/mol=386.65g/mol=386.65g/mol
Moles in 0.1 L0.1\>L0.1L =0.1×5.04×10−3=5.04×10−4moles=0.1×5.04×10^{-3}\\=5 .04×10^{-4}moles=0.1×5.04×10−3=5.04×10−4moles
Mass =5.04×10−4×386.65=5.04×10^{-4}×386.65=5.04×10−4×386.65
=0.19487g=0.19487g=0.19487g
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