Question

how much space would 2.56 moles of xenon gas occupy at STP

Answer 1

Task:

How much space would 2.56 moles of xenon gas occupy at STP?

Solution:

STP (standard temperature and pressure):

T = 273K

P = 1 atm

The Ideal Gas Law shows how the volume of gas depends on pressure, temperature and amount of gas.

P·V = n·R·T

P – pressure of gas

V – volume (L)

n – amount of gas (mol)

T – temperature (K)

R – universal gas constant (0.082 L·atm·mol⁻¹·K⁻¹)

V = n·R·T / P

The volume of 2.56 mol of gas at STP is

V = 2.56 · 0.082 · 273 / 1 = 57.3 L

Or the second way we can find the volume of the gas at STP is using Avogadro Law.

Avogadro law: 1 mol of gas at STP occupies 22.4 L (it doesn't depend on the kind of gas).

We have 2.56 mol of gas that's why The volume is V = 2.56 · 22.4 = 57.3 L

Answer: V = 57.3 L