To 5.0 L ideal gas, 1.0 kJ of heat is added. The gas expands against a constant external pressure of 1.0 bar to a final volume of 8.0 L. What is the change internal energy for the gas (1.0 L.bar = 0.10 kJ)
A.
0.30 kJ
B.
0.70 kJ
C.
1.3 kJ
D.
1.8 kJ
8-5 = 3L
= 1× 4.875 × 1.10kj
= 6.9625kJ
6.9625×0.1=
=0.70kJ
Comments
Leave a comment