Question #266864

a substance was exposed to radiation of wavelength 4.2x10^-6 m^-1 ;if the frequency difference between the first stokes line and the first anti stokes line is 7.6x10^4 m^-1, calculate the frequencies of two lines.


1
Expert's answer
2021-11-17T04:29:02-0500

wavelength =4.2×106m1=4.2×10^{-6} m^{-1}


Frequency=1TFrequency =\frac {1}{T} Or velocitywavelength\frac{velocity }{wavelength }


Velocity =(4.2×106)×(7.6×104)=0.3192= (4.2×10^{-6})× (7.6×10^4 )= 0.3192



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