a substance was exposed to radiation of wavelength 4.2x10^-6 m^-1 ;if the frequency difference between the first stokes line and the first anti stokes line is 7.6x10^4 m^-1, calculate the frequencies of two lines.
wavelength =4.2×10−6m−1=4.2×10^{-6} m^{-1}=4.2×10−6m−1
Frequency=1TFrequency =\frac {1}{T}Frequency=T1 Or velocitywavelength\frac{velocity }{wavelength }wavelengthvelocity
Velocity =(4.2×10−6)×(7.6×104)=0.3192= (4.2×10^{-6})× (7.6×10^4 )= 0.3192=(4.2×10−6)×(7.6×104)=0.3192
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