Interpreting the values in the tables and aligning them
Exp123A(m)0.0400.0400.080B(m)0.0400.0800.080initialrate2.2×10−44.4×10−48.8×10−4
Working
Rate1Rate2=2.2×10−44.4×10−4=k(0.04)x(0.04)yk(0.04)x(0.08)y
2=2y⟹y=1
Rate2Rate3=4.4×10−48.8×10−4=k(0.040)x(0.080)yk(0.080)x(0.080)y
2=2x⟹x=1
Substituting data for trial 1,
2.2×10−4=k(0.04)1(0.04)1
K=0.1375M−1s−1
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