Question

Methanol is produced according to the following equation:

CO(g) + 2H2(g) ⇄ CH3OH(g)

In an experiment, 1.000 mol each of CO and H2 were allowed

to react in a sealed 10.0-L reaction vessel at 500 K. When the

equilibrium was established, the mixture was found to contain

0.0892 mole of CH3OH. What are the equilibrium

concentrations of CO, H2 and CH3OH? Calculate the

equilibrium constants Kc and Kp for this reaction at 500 K?

(R = 0.0821 L.atm/Mol.K)

Answer 1

0.0821(0.0892) ×500×10

= 3.67×10²