How many moles of hydrosulphate acid are there in 27.0 g of hydrosulphate acid if the density of hydrosulphate acid is 1.84 g/cubic centimeter. what is the concentration in %m/m of 250 cubic centimeter in weighing 350 g?
1
Expert's answer
2013-03-15T09:42:14-0400
To find the amount of H2SO4 in moles we should use the formula
n(moles) = m(g)/MW(g/mol) MW(H2SO4) = 2 x 1 + 32 + 16 x 4 = 98 g/mol n(H2SO4) = 27.0/98.0 = 0.276 mol The concentration of H2SO4 is w(%) = m(H2SO4, g)/m(solution of H2SO4, g) x 100% The weight of 250 cm^3 of solution is m(H2SO4) = V(cm^3) x p(g/cm^3) = 250 x 1.84 = 460 g w(%) = 350 / 460 x 100% = 76.1 %
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment