Answer to Question #257460 in Physical Chemistry for pawan

Question

The experimental rate law of a reaction A + B → C is v = k[A]2[B]. (a) Determine to- tal order of the reaction. (b) Imagine initial conditions at which the rate equals v0. If the concentration of reagent A is doubled and the concentration of B is halved, what will happen with the reaction rate? 

Answer 1

The rate law expression is, rate=$\frac{k[A] 0 p ​ }{ [B] 0 q} ​ .$

The rate constant of a reaction does not depend upon concentrations of the reactants. Thus, it will remain the same. The rate constant of a reaction depends on temperature not on concentration.