Answer to Question #254582 in Physical Chemistry for saloni

Question

In our college laboratory a container containing 5 litres of a commercial sample of

hydrochloric acid (36.2 % by weight with a density of 1.19 g/ml) developed a crack and all

the HCI was spilt on the floor. It can be neutralised with limestone powder.

(atomic masses: Ca = 40, C = 12, 0 = 16]

(a) Write the equation for the reaction between limestone and hydrochloric acid.

(b) How many moles of hydrochloric acid was spilt?

Answer 1

CaCO3​+2HCl→CaCl2​+H2​O+CO2​

Molar mass of HCl= 36.458

5000×36.2/100= 1810g

1810/36.458= 49.65moles