Answer to Question #249801 in Physical Chemistry for mad

Question #249801

When 5.73 g of sodium chloride (NaCl) dissolves in 100 cm³ of water, the temperature of the water fell from 22.4 ^oC to 19.8 ^oC. Calculate the enthalpy change of the reaction.

Expert's answer

∆H = m x s x ∆T

= 5.73× 100×(22.4-19.8)

= 1489.8J/mol

Learn more about our help with Assignments: Physical Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. 50 mL of a water sample consumed 28.2 mL of EDTA upon titration. The water was treated with zeolit
2. A radioactive sample with a half-life of 3hrs contains 25-mCi radioactivity. The radioactivity of t
3. How did you account for the abnormally high mobility of OH- ions in water?
4. The equilibrium constant for a particular reaction is 10^ -12 at 327 degree Celsius and 10^ -7 at 42
5. For a particular chemical reaction, the free energy changes at 25 degree Celsius and 35 degree Celsi
6. 4. A sample of water was alkaline to both phenolphthalein and methyl orange. 100 mL of this water
7. what is ligands?