Question #248629

The equilibrium constant for a particular reaction is 10^ -12 at 327 degree Celsius and 10^ -7 at 427 degree Celsius. Calculate the enthalpy of reaction.


1
Expert's answer
2021-10-10T10:25:25-0400

Degrees into kelvin

327+273=600K327+273=600K

427+273=700K427+273=700K



The equilibrium constant KpK_p ​ for the reaction


A(g)⇌B(g)+C(g)


Kp1=1012K_{p1​}=10^{-12} at 600k600k

Kp2=107K_{p2​}=10^{-7} at 700K700K



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