The equilibrium constant for a particular reaction is 10^ -12 at 327 degree Celsius and 10^ -7 at 427 degree Celsius. Calculate the enthalpy of reaction.
Degrees into kelvin
327+273=600K327+273=600K327+273=600K
427+273=700K427+273=700K427+273=700K
The equilibrium constant KpK_pKp for the reaction
A(g)⇌B(g)+C(g)
Kp1=10−12K_{p1}=10^{-12}Kp1=10−12 at 600k600k600k
Kp2=10−7K_{p2}=10^{-7}Kp2=10−7 at 700K700K700K
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