Answer to Question #248629 in Physical Chemistry for Devendra

Question

The equilibrium constant for a particular reaction is 10^ -12 at 327 degree Celsius and 10^ -7 at 427 degree Celsius. Calculate the enthalpy of reaction.

Answer 1

Degrees into kelvin

$327+273=600K$

$427+273=700K$

The equilibrium constant $K_p$ ​ for the reaction

A(g)⇌B(g)+C(g)

$K_{p1​}=10^{-12}$ at $600k$

$K_{p2​}=10^{-7}$ at $700K$