Na-24 half life = 15h
We know that for first order reaction
"t \\frac{1}{\n\n2}\n\n\n\n\u200b\t\n\n = \n\n\n\n\\frac{0.693}{K}"
"Therefore, K = \\frac{0.693}{t\\frac{1}{2}} \n\n\u200b"
"K= \\frac{0.693}{15h}= 0.0462h^{-1}"
At starting, (Activity)0 = 2.5x109d/s
At 4days, 4×24hr= 96hr
96×2.5×109
= 2.4×1011 d/s
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