Na-24 half life = 15h
We know that for first order reaction
t12=0.693Kt \frac{1}{ 2} = \frac{0.693}{K}t21=K0.693
Therefore,K=0.693t12Therefore, K = \frac{0.693}{t\frac{1}{2}} Therefore,K=t210.693
K=0.69315h=0.0462h−1K= \frac{0.693}{15h}= 0.0462h^{-1}K=15h0.693=0.0462h−1
At starting, (Activity)0 = 2.5x109d/s
At 4days, 4×24hr= 96hr
96×2.5×109
= 2.4×1011 d/s
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