A reaction of 22.85 g of sodium hydroxide with 20.82 g of hydrogen chloride produces 10.29 g of water and x g of sodium chloride
NaOH + HCl → NaCl + H₂O
To find mass of NaCl produced we need to determine the moles of water produced. As when 1 mole of water is produced, 1 mole of NaCl is also produced we can find moles of NaCl and its mass, thus:
Moles H₂O -Molar mass: 18.015g/mol-
10.29g * (1mol / 18.015g) = 0.5712 moles H₂O = 0.5712 moles NaCl
Now, the mass of NaCl -Molar mass: 58.44g/mol- is:
0.5712 moles NaCl * (58.44g / mol) =
33.38g of NaCl are produced
0.03338kg of NaCl are produced
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