Answer to Question #238081 in Physical Chemistry for Ashok

Question

6. The EMF of cell, Cd(s)/Cd2+(0.01M) // Cu2+ (0.5 M)/Cu is 0.79 V. Determine the standard reduction potential of Cd electrode, if the standard electrode potential of copper is 0.34 V

Answer 1

Given that

$E_0$ Cell = 0.34V

E_c Cell = O

Cu²⁺= ?

The EMF of the electrode when dipped in different concentrated solution is given by nernst equation;

E_c Cell = E₀ cell + 20.059 log Cu²⁺

0 = 0.34 + 20.059 log (Cu²⁺)

log Cu²⁺ = -0.34 × 0.0295

Log Cu²⁺ = -11.52

Cu²⁺ = 2.98 × 10^-12m