Question #237127

five indigestion tablets containing calcium carbonate with a total mass of 2.50g were added to 50.0cm^3 of1.00mol dm^-3 hydrochloric acid.

CaCO3+2HCl--> CaCl2+CO2 +H2O

after reaction the solution was transferred to a 250cm^3 volumetric flask and the volume made up to 250cm^3 using deionised water. 25.0cm^3 samples of the solution were titrated against 0.126mol dm^-3 sodium hydroxide solution.

NaOH+HCl--> NaCl+H2O

the average titre was 11.30cm^3.

a) calculate the mass of calcium carbonate (in grams) in the five tablets.

give your answer to 3 significant figures.(AO2)

b) calculate the percentage of calcium carbonate in the tablets.(AO2)


1
Expert's answer
2021-09-15T02:41:24-0400


Moles of CaCO3=2.50100.0869=0.025molesCaCO_3=\frac{2.50}{100.0869}=0.025 moles


Moles of HCl=2×0.025=0.05molesHCl=2×0.025=0.05moles



Mass in the five tablets = 2.50 grams


Moles of HCl=1.00×50.01000=0.05=1.00×\frac{50.0}{1000}=0.05



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