Answer to Question #233380 in Physical Chemistry for Arbi

Question

The specific conductance of 0.02 M KCL at 20 degree Celsius determine using conductivity water was found to be 0.2765sm-1 if the resistance of the solution of 400 ohm, calculate the cell constant

Answer 1

Given for (N/50) solution

k=0.2765 Scm −1

,R=400ohm

K = 1/r × 1/a

0.2765 = 1/400 × cell constant

0.2765 = 0.0025 cell constant

= 110.6cm^-1