Calculate the pH of an aqueous solution of 0.01 M sodium acetate. State any assumption made in your calculations. (Ka of acetic acid is 1.75 x 10-5 mol L-1 at 25 ˚C in water.)
Neglecting [H+], the mass balance equations give [CH3COO ] + [CH3COOH] = 0.01 [CH3COOH] = [OH ] + [HCO3 ] Without carbonic acid we get [CH3COOH] = [OH ] and [CH3COO ]=0.1; then[OH ]2 = 0.01×10 -9.24 and pH = 8.9
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