Question #230456
consider the reaction
KMnO4 + 5FeCl2 + 8HCl =MnCl2 + 5FeCl3 + 4H2O + KCl
if 24.0 mol of FeCl2 and 13.0 mol KMnO4 are mixed with excess HCl, how many moles of MnCl2 can be formed
KMnO4 + 5FeCl2 + 8HCl =MnCl2 + 5FeCl3 + 4H2O + KCl
if 24.0 mol of FeCl2 and 13.0 mol KMnO4 are mixed with excess HCl, how many moles of MnCl2 can be formed
Expert's answer
Mole ratio of MnCl2 :KMnO4 = 1:1
13 KMnO4 = 13MnCl2
Mole ratio of MnCl2 : FeCl2 = 1:5
= 24/5 = 4.8 moles
Mole ratio of MnCl2: HCl = 1:8
= 1/8 = 0.125
= 13+0.125 + 4.8
= 17.925 moles
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#340153 on Dec 2023
#340153 on Dec 2023
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