To calculate the entropy change of the system for the combustion of one mole of methane gas at 298K. Standard entropies at 298K are as follows:
S⁰(CO₂)=213.7JK⁻¹
S⁰(H₂O)=69.9JK⁻¹
S⁰(CH₄)=186.3JK⁻¹
S⁰(O₂)=205.1JK⁻¹
Also calculate the entropy change of surroundings if the molar enthalpy of combustion of methane is -8.9×10⁵Jmol⁻¹
CH4 + 2O2 → CO2 + 2H2O
"\u2206H = 186.3+2(205.1)+213.7+2(69.9)=950 Jk^{-1}"
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