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Answer to Question #223147 in Physical Chemistry for Varylan
Question #223147
A certain natural decay series stars with 92238U and ends with 82204Pb. Each step involves the loss of either an α-particle or a β-particle. What is the number of α-particles released?
What is the number of β-particles released?
Expert's answer
α-particles = 238-204 = 34
β-particle = 92-82 = 10
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