Answer to Question #22236 in Physical Chemistry for BasedBros

Question

. determine the mass of water that absorbs 1234 J of heat and undergoes a temperature change of 33.4oC.

Answer 1

Heat is evaluated asQ=c*m*(t₂-t₁)
where m is mass and c is specific heat capacity.
In our case t₂-t₁=33.4. so we find mass
m = Q/(c*(t₂-t₁)) = 1234/(4200*33.4) = 0.0088 kg = 8.8g
mass of water is 8.8 g