1a)Calculate the pressure exerted by 1 mole of methane in a 250ml container at 300k using vanderwaal's equation
1b) what pressure will be predicted by ideal gas equation
a=2.253L^2atm/mol^2
b=0.0428L/mol
R=0.0821Latm/mol/k
Volume = 2501000=0.25l\frac{250}{1000}=0.25l1000250=0.25l
[P+n2aV2][V−nb]=nRT[P+\frac{n^2a}{V^2}][V-nb]=nRT[P+V2n2a][V−nb]=nRT
(P+2.2530.25×0.25)(0.25−0.0428)=0.0821×300(P+\frac{2.253}{0.25×0.25})(0.25-0.0428)=0.0821×300(P+0.25×0.252.253)(0.25−0.0428)=0.0821×300
(P+36.048)(0.2072)=24.63(P+36.048)(0.2072)=24.63(P+36.048)(0.2072)=24.63
P+36.048=118.87P+36.048=118.87P+36.048=118.87
P=82.82P=82.82P=82.82 atm
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