M = n/V where n is the number of moles and V is the volume in litres,
d = density = 1.83 g/ml = 1830 g/L,
ie. weight of H2SO4 is 1830 g in 1 L of solution,
But H2SO4 is present 96.6% by weight in the solution i.e 0.966 x 1830 = 1767.78 g,
So M = n/V = 1767.78/98/1 where 98 is the molar mass of H2SO4,
= 18.039 m/L
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