The metallic iron have a cubic structure. The edge length of the unit cell is 287 pm. The density of the solid is 7.87 g/cm3. Calculate the number of Fe atoms per unit cell
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Expert's answer
2013-01-28T09:54:18-0500
Volume of the unit cell = (287 pm)^3 = 2.364 * 10^7 pm^3 (2.364 * 10^7 pm^3)(10^-10 cm/pm)^3 = 2.364 × 10^-23 cm^3
mass of one mole of unit cells = (7.87 g/cm^3)(2.364 × 10^-23 cm^3)(6.022 ×10^23 /mol) = 112.04 g/mol of cells
Since the mass of a mole of iron is 55.845 g/mol, 112.04 g is 2 mol of iron.
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