For a solution that is 0.164 M NH3 and 0.102 M NH4Cl, calculate the [OH-] and the pH value.
pH for a buffer solution of weak base and its salt is = pH =14- pkb+log {[salt] /[Base]}
Now pH= 14-4.74 +log (0.102/0.164)
=9.05
So pH of the solution is 9.05
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