Question

Q. 90 ml of pure dry O2 is subjected to silent electric discharge. If only 10% of it is converted to O3 , volume of mixture of gases (O2,O3) after the reaction will be----and after passing through turpentile oil will be......
(i)84 ml and 78 ml (ii) 81 ml and 87 ml (iii) 78 ml and 84 ml (iv) 87 ml and 81 ml

Answer 1

10% of& 90 ml is 9 ml
9 ml of O2 can produce x ml of O3
9ml x
1.5 O2 ----->& O3
& 1.5 & 1

x=6
volume of mixture of gases (O2,O3) after the reaction will be 90-9+6=87 ml
volume of mixture of gases (O2,O3) after the reaction and after passing through turpentile oil will be 87-6=81

So (iv) 87 ml and 81 ml