Question

A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure, has its volume increased to 34 liters and its temperature decreased to 35 °C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?

Answer 1

For answering this question,you need to usenext equation

P₁V₁/T₁ = P₂V₂/T₂
P₁ = P₂V₂T₁/T₂V₁
P₁ = 2.0 * 34 * 45 / 35* 28 = 3.12 atm