A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure, has its volume increased to 34 liters and its temperature decreased to 35 °C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?
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Expert's answer
2012-12-24T10:42:04-0500
For answering this question,you need to usenext equation
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Comments
You need tro convert Celsius to Kelvin first though. So P1 = (2 atm)(34L)(318K)/(28L)(308K) --> 2.507 atm (not 3.12)
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