Question

Consider the following reaction: N2O4 (g) → 2 NO2 (g) Assume that an experiment is carried out in which the starting concentration of N2O4 (g) is 0.100 mol/L. No products are present at the beginning of the reaction. When equilibrium is established, the concentration of NO2 (g) is 2.43 x 10-2 mol/L. Calculate the equilibrium constant for the above reaction.

Answer 1

$k= \frac {[NO_2]^2} {[N_2O_4]} = 5.9 ×10^{-3}$