the enthalpy and entropy change for the reaction are -3.9KJ/ mol and + 56.6J/ mol K respectively at 25 degree celcius. what is the free energy change in kj/ mole? is this reaction always spontaneous never spontaneous or does it depend on the Temperature?
∆G = ∆H - ∆TS
∆H = -3.9KJ/mol
T = 25 + 273 = 298K
∆S = 56.6J/mol = 0.056KJ/mol
∆G = -3.9 - 298(0.056)
= -3.9 - 16.688
= -20.588KJ/mol
The reaction is spontaneous
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