Answer to Question #205614 in Physical Chemistry for Sydney

Question

175 grams of hot aluminum at 100.0ºC is dropped into an insulated cup that contains 40.0 mL of ice cold water at 0.00ºC (all liquid). Find the final temperature after they reach thermal equilibrium. The specific heat of Al = 0.900 J/gºC.

Answer 1

setting the heat values derived given the equation:

q=mCsΔT

equal to each other, as such,

q water+q(Al)=0

∴qwater=−q(Al)

Before we start, I will assume the density of water is 1.00 g/mL

water is 1.00 g/mL

.

40.0g⋅ 4.184J/g × °C × (Tf−0°C)=−[175g×0.9J/g⋅°C⋅ (Tf−100°C)]

Tf−167.36°C=−100Tf+157.5°C

101Tf=324.86°C

∴Tf=3.22°C