Question #20414
Q. 0.01 mole of iodoform (CHI3) reacts with Ag to produce a gas whose volume at NTP is
(i) 224 ml (ii) 112 ml (iii) 336 ml (iv) none of this
(i) 224 ml (ii) 112 ml (iii) 336 ml (iv) none of this
Expert's answer
2СHI3+ 6Ag = 6AgI + C2H2
n(C2H2) = 0.005 mol.
V(C2H2) = 112 ml
n(C2H2) = 0.005 mol.
V(C2H2) = 112 ml
