The molality of 0.05 mol hcl in 5 litre solution at 4°c
Let the volume of the solution be 1 litre
Molarity = moles of NaOH/volume of the solution in litres
0.05 moles of NaOH
Mass of solvent = Volume × Density
= 1×1
= 1Kg
Molar Mass of NaOH = 39.997 × 0.05
= 1.99985
= 1.99985/1
= 1.99985
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