Question

What is the activity of Ag+ in an electrochemical cell if the activity Zn2+ is 0.0167 and Ecell is +1.50 V?

Answer 1

$E_0cell=E_0red-E_0oxid$

$1.50V=E_0red-0.0167$

$E_0red=1.50+0.0167$

$E_0red=1.5167V$