one mole of an ideal gas is allowed to expand at 25 degree celsius till its pressure falls to one- fifth of its original pressure. find out the free energy
E=−2.303×nRTlogP1P2E=−2.303×nRTlog\frac{P_1}{P_2}E=−2.303×nRTlogP2P1
E=−2.303×1×8.314×298log10.2=3.98kJE=-2.303×1×8.314×298log\frac{1}{0.2}=3.98kJE=−2.303×1×8.314×298log0.21=3.98kJ
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