The heat of combustion of 2-propanol at 298.15 K, determined in a bomb calorimeter, is -
33.41 kJ/g. For the complete combustion of one mole of 2-propanol, determine (a) ΔE, and (b)
ΔH.
a) ΔE=−46.7kJ/gΔE =-46.7kJ/gΔE=−46.7kJ/g
b) ΔH=−18.4kJ/gΔH=-18.4kJ/gΔH=−18.4kJ/g
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