Question #199825

The heat of combustion of 2-propanol at 298.15 K, determined in a bomb calorimeter, is -

33.41 kJ/g. For the complete combustion of one mole of 2-propanol, determine (a) ΔE, and (b)

ΔH.


1
Expert's answer
2021-05-31T02:25:50-0400

a) ΔE=46.7kJ/gΔE =-46.7kJ/g


b) ΔH=18.4kJ/gΔH=-18.4kJ/g


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