Question #19513

70kg of Masa is heated from -24.0c to 85.0c . Her M.p is 10.0c and her boiling point us 95.oC . How much energy did she lose ? Csolid=1500j/kgC , Cliquid =3800j/kgc Cgas =2100 J/KgC Lf 56000J/kg Lv=20000j/kg
Can you please help me answering this question ? Thank you

Expert's answer

Question#19513

70kg of Masa is heated from -24.0c to 85.0c. Her M.p is 10.0c and her boiling point us 95.oC. How much energy did she lose? Csolid=1500j/kgC, Cliquid =3800j/kgc Cgas =2100 J/KgC Lf 56000J/kg Lv=20000j/kg

Can you please help me answering this question? Thank you

Solution:

Let:


m=70 kgm = 70 \text{ kg}T1=24CT_1 = -24^\circ\text{C}T2=85CT_2 = 85^\circ\text{C}Tf=10CT_f = 10^\circ\text{C}ce=1500 j/kgCc_e = 1500 \text{ j/kg}^\circ\text{C}ci=3800 j/kgCc_i = 3800 \text{ j/kg}^\circ\text{C}Lf=2100 j/kgCL_f = 2100 \text{ j/kg}^\circ\text{C}


Q - ?


Q=Qe+Qf+Qi,were: Qeenergy needed to heated solid,Qfenergy needed to fusion,Qienergy needed to heated liquidQ = Q_e + Q_f + Q_i, \quad \text{were: } Q_e - \text{energy needed to heated solid}, \\ Q_f - \text{energy needed to fusion}, \quad Q_i - \text{energy needed to heated liquid}Q=mceΔT+mLf+mciΔTQ = m c_e \Delta T + m L_f + m c_i \Delta TQ=701500(10(24))+702100+703800(8510)=23667 kJQ = 70 * 1500(10 - (-24)) + 70 * 2100 + 70 * 3800(85 - 10) = 23667 \text{ kJ}


Answer: 23667 KJ.

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