Answer to Question #194503 in Physical Chemistry for Gazza

Question

Determine the mass of Lead (II) Iodide produced if 9.70g of lead (II) nitrate reacts with excess sodium iodide

Answer 1

Pb(NO3)2 +2NaI --->2NaNO3 + PbI2

$Moles[Pb(NO_3)_2]= \frac{9.70}{331.2}=0.0293mol$

$Moles [NaNO_3]=2×0.0293=0.0586mol$

$Mass [NaNO_3]= 149.89×0.0586=8.782 grams$