why is work(w=pex*deltaV) negative ?
When you move a positive charge into higher potential,you do work on it. W = q*deltaV. Similarly, if you move a negative charge from high voltage to low voltage, work is done on the charge. q is negative, but so is the change in voltage.
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!