How many grams of CO2 are produced when 100 g C4H10 undergoes combustion with 200 g O2?
Use the following molar masses: C4H10=58g/mol, O2=32 g/mol and CO2=44g/mol.
2(C4H10) + 13O2 → 8CO2 + 10H2O
Moles of C4H10=10058=1.72molesC_4H_{10 }= \frac{100}{58}=1.72molesC4H10=58100=1.72moles
Moles of O2=20032=6.25molesO_2= \frac{200}{32}=6.25molesO2=32200=6.25moles
Moles of CO2=1.72×82=6.88molesCO_2= \frac{1.72×8}{2}=6.88molesCO2=21.72×8=6.88moles
Mass of CO2=6.88×44=302.72gCO_2= 6.88×44=302.72gCO2=6.88×44=302.72g
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments